def fun(num): ····l = [] ····for i in range(num): ········if i % 3 == 0 and i % 10 == 6: ············l.append(i) ····return l c = fun(200) print(*c,sep=' ') print('复核条件的数有%d个'%len(c))
def fun1(a,b): return (a,b,abs(a-b)) print("|{}-{}|={}".format(*fun1(1,5))) def fun2(): return [i for i in range(200) if i%3==0 and i%10==6] print(*fun2()) def fun3(i): return [i,i,i,abs(i*i*i)] print("|{}*{}*{}|={}".format(*fun3(-2)))