我是没找到,自己根据官方算距离的方法自己写了个JAVA的,希望能帮到其他论坛各种搜的朋友
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private final static double DEF_PI = 3.14159265359; // PI
private final static double DEF_PI180 = 0.01745329252; // PI/180.0
private final static double DEF_R = 6370693.5; // radius of earth
/**
* 根据圆心、半径算出经纬度范围
*
*
@param x
* 圆心经度
* @param y
* 圆心纬度
* @param r
* 半径(米)
*
@return double[4] 南侧经度,北侧经度,西侧纬度,东侧纬度
*/
public static double[] getRange(double lon, double lat, int r) {
double[] range = new double[4];
// 角度转换为弧度
double ns = lat * DEF_PI180;
double sinNs = Math.sin(ns);
double cosNs = Math.cos(ns);
double cosTmp = Math.cos(r / DEF_R);
// 经度的差值
double lonDif = Math.acos((cosTmp - sinNs * sinNs) / (cosNs * cosNs)) / DEF_PI180;
// 保存经度
range[0] = lon - lonDif;
range[1] = lon + lonDif;
double m = 0 - 2 * cosTmp * sinNs;
double n = cosTmp * cosTmp - cosNs * cosNs;
double o1 = (0 - m - Math.sqrt(m * m - 4 * (n))) / 2;
double o2 = (0 - m + Math.sqrt(m * m - 4 * (n))) / 2;
// 纬度
double lat1 = 180 / DEF_PI * Math.asin(o1);
double lat2 = 180 / DEF_PI * Math.asin(o2);
// 保存
range[2] = lat1;
range[3] = lat2;
return range;
}
public static double getLongDistance(double lon1, double lat1, double lon2, double lat2) {
double ew1, ns1, ew2, ns2;
double distance;
// 角度转换为弧度
ew1 = lon1 * DEF_PI180;
ns1 = lat1 * DEF_PI180;
ew2 = lon2 * DEF_PI180;
ns2 = lat2 * DEF_PI180;
// 求大圆劣弧与球心所夹的角(弧度)
distance = Math.sin(ns1) * Math.sin(ns2) + Math.cos(ns1) * Math.cos(ns2) * Math.cos(ew1 - ew2);
// 调整到[-1..1]范围内,避免溢出
if (distance > 1.0)
distance = 1.0;
else if (distance < -1.0)
distance = -1.0;
// 求大圆劣弧长度
distance = DEF_R * Math.acos(distance);
return distance;
}
public static void main(String args[]) {
double x1 = 13.957503;
double y1 = 49.77837;
double r[] = getRange(x1, y1, 100000);
System.out.println(r[0]);
System.out.println(r[1]);
System.out.println(r[2]);
System.out.println(r[3]);
System.out.println(getLongDistance(x1, y1, r[0], y1));
System.out.println(getLongDistance(x1, y1, r[1], y1));
System.out.println(getLongDistance(x1, y1, x1, r[2]));
System.out.println(getLongDistance(x1, y1, x1, r[3]));
}
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