【面码酱出题】一个随机数的生成

rand？线性求余？

其实perfect代码如下：
unsigned int ran( ) { return 6;//obtain by rolling a dice
}

前排持久关注

int GetRand(int x)
{
if ( x < 0 ) x = - x;
if ( x == 0 ) return 0;
if ( x == RAND_MAX ) return rand( );
if ( x < RAND_MAX )
while ( 1 ) { int i = rand( ); if ( i / x != INT_MAX / x ) return i; }
if ( x % RAND_MAX == 0 ) return rand( ) * ( x / RAND_MAX );
while ( 1 ) { int i = rand( ) * ( x / RAND_MAX ); if ( i >= x % RAND_MAX ) return i - x % RAND_MAX; }
}

好吧 我只会这个：
int GetRand(int x)
{
srand((unsigned)time(NULL));
return rand()%(x+1);
}

int GetRand(int X)
{
return X ? X - 1 : 0;
}

if ( x % RAND_MAX == 0 ) return rand( ) * ( x / RAND_MAX ) + GetRand( x / RAND_MAX - 1 );

int GetRand(int x)
{
if ( x < 0 ) x = - x;
if ( x == 0 ) return 0;
if ( x == RAND_MAX ) return rand( );
if ( x < RAND_MAX )
while ( 1 ) { int i = rand( ); if ( i / x != INT_MAX / x ) return i % ( x + 1 ); }
if ( x % RAND_MAX == 0 ) return rand( ) * ( x / RAND_MAX ) + GetRand( x / RAND_MAX - 1 );
while ( 1 ) { int i = rand( ) * ( x / RAND_MAX ); if ( i >= x % RAND_MAX ) return i - x % RAND_MAX; }
}I

int GetRand(int X){
int result;
do{
__(char*)(&result)[0]=rand()*(rand()>16383?1:-1);
__(char*)(&result)[1]=rand()*(rand()>16383?1:-1);
__(char*)(&result)[2]=rand()*(rand()>16383?1:-1);
__(char*)(&result)[3]=rand()*(rand()>16383?1:-1);
}while(result>X);
return result;
}
对不起我是来搞笑的I

int GetRand(int x)
{
if ( x < 0 ) x = - x;
if ( x == 0 ) return 0;
if ( x == RAND_MAX ) return rand( );
if ( x < RAND_MAX )
while ( 1 ) { int i = rand( ); if ( i / x != INT_MAX / x ) return i % ( x + 1 ); }
if ( x % RAND_MAX == 0 ) return rand( ) * ( x / RAND_MAX ) + GetRand( x / RAND_MAX - 1 );
while ( 1 ) { int i = rand( ) * ( x / RAND_MAX + 1 ); if ( i >= x % RAND_MAX ) return i - x % RAND_MAX; }
}I

get_random_bytes什么的