怎么把这个curl该成phpcurl的形式，我改成这样还是不对
curl -i -s -k -X 'POST' \
-H 'Origin: http://192.168.252.8' -H 'User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/38.0.2125.122 Safari/537.36 SE 2.X MetaSr 1.0' -H 'Content-Type: application/x-www-form-urlencoded' -H 'Referer: http://192.168.252.8/0.htm' \
-b 'myusername=1241402538; username=1241402538; smartdot=12358' \
--data-binary $'DDDDD=1241402538&upass=12358&0MKKey=%B5%C7+%C2%BC' \
'http://192.168.252.8/0.htm'
curl -i -s -k -X 'POST' \
-H 'Origin: http://192.168.252.8' -H 'User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/38.0.2125.122 Safari/537.36 SE 2.X MetaSr 1.0' -H 'Content-Type: application/x-www-form-urlencoded' -H 'Referer: http://192.168.252.8/0.htm' \
-b 'myusername=1241402538; username=1241402538; smartdot=12358' \
--data-binary $'DDDDD=1241402538&upass=12358&0MKKey=%B5%C7+%C2%BC' \
'http://192.168.252.8/0.htm'
